Difficult question! for experts only - The answer!

 

Hole Cards

• Player A:

  • K♥ A♣ K♠ K♦ → Four kings + ace

• Player B:

  • T♠ T♣ T♥ T♦ → Four tens

Board:

K♣ Q♣ Q♠ J♣ 9♣

---

Step 1: Omaha Rules Recap

• Each player must use exactly two hole cards and exactly three cards from the board to make their best five-card hand.

---

Step 2: Board Evaluation

The board is:
K♣ Q♣ Q♠ J♣ 9♣
This includes five cards, of which four are clubs, so a flush is possible.
Also, the board is very connected (Q, J, T, 9), so straights are possible.

---

Step 3: Player Hands

Player A Analysis

• Hole cards: K♥ A♣ K♠ K♦

• Player A has four kings, but can only use two hole cards.

• Best possible combo from A's hole cards: A♣ + K♠

  • Combine with board: K♣ Q♣ J♣ (to complete a club flush with A♣ high)

  • This gives Player A the nut flush: A♣ K♣ Q♣ J♣ 9♣

Player B Analysis

• Hole cards: T♠ T♣ T♥ T♦ (four tens)

• Possible combo: T♣ + T♥ (or any other two tens)

• Combine with board: Q♣ J♣ 9♣ → also a club flush, but the best possible for B is T♣ J♣ Q♣ 9♣ X

  • Highest club B has is T♣

  • Therefore, Player B has a T-high flush

---

Step 4: Compare Final Hands

• Player A: Ace-high flush (A♣ K♣ Q♣ J♣ 9♣)

• Player B: Ten-high flush (T♣ Q♣ J♣ 9♣ 8♣ — but 8♣ isn't on board or in hand, so highest possible is T♣ Q♣ J♣ 9♣ [one more club from hand] — still weaker)

---

✅ Winner: Player A

With the nut flush (ace-high flush).
Despite both players having very strong hole cards (quads each), only two hole cards count, and Player A uses A♣ to form a better flush.